spot the differentiation

piss-poor so i'm off to bed
From the
Games For Geeks challenge. See all
149 entries (closed)
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FiiiiiiveGoldenFanjitas, Wed 9 Nov 2005, 23:16,
archived)
quite woosome
but my head cannae explain peaks and troughs or whatevrr
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executiverocker is going to post a thread on Reddit, Wed 9 Nov 2005, 23:18,
archived)
bloody triggernomitry
or how you spell it dave
EDIT: the calculator i used for Alevel math for these i stole off a 12 year old, how brilliant, £8 saved
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executiverocker is going to post a thread on Reddit, Wed 9 Nov 2005, 23:22,
archived)
if i coulf be botherd id work out
the line equation o those graphs...
but i cant be arsed
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Sir T. Skellington LIMES ARE FOR CUNTS!, Wed 9 Nov 2005, 23:18,
archived)
hmmm
and that would take A LOT of working out
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FiiiiiiveGoldenFanjitas, Wed 9 Nov 2005, 23:19,
archived)
not really
just need 3 points on a graph
2 intercections of X
and 1 intersection of Y
and you get somthing like Y=X
3 =(a x pi)X
2+(b x pi)X+c
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Sir T. Skellington LIMES ARE FOR CUNTS!, Wed 9 Nov 2005, 23:22,
archived)
ta
but im not going to do it as i cant be arsed typing out the HTML to get sup script
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Sir T. Skellington LIMES ARE FOR CUNTS!, Wed 9 Nov 2005, 23:25,
archived)
that may be true actually
tis just a sign-wave graph
polynomial: -

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Sir T. Skellington LIMES ARE FOR CUNTS!, Wed 9 Nov 2005, 23:28,
archived)
yup
let stop this thread...
much to late for maths talk
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Sir T. Skellington LIMES ARE FOR CUNTS!, Wed 9 Nov 2005, 23:32,
archived)
err...
cos(x) = 1 - x^2/2! + x^4/4! - ... (a polynomial)
sin(x) = x - x^3/3! + x^5/5! - ... (a polynomial)
aicmfp again!
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grey matter, Wed 9 Nov 2005, 23:39,
archived)
In a polynomial the powers have to be positive integers
Gimmie my five pounds back you fraud!
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Guineapiggy Fuzzeh!, Wed 9 Nov 2005, 23:45,
archived)
i think i should be charging for these lessons...
a) powers don't have to be positive for it to be classed as a polynomial (I think)b) they aren't even negative in the above.
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grey matter, Wed 9 Nov 2005, 23:51,
archived)
piss poor!
The first is the differential of the second.
As proved by a complex Euclidian representation of either.
/cunt.
(
Papagato RackSpanner, Thu 10 Nov 2005, 0:19,
archived)