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# not really
just need 3 points on a graph

2 intercections of X

and 1 intersection of Y

and you get somthing like Y=X3 =(a x pi)X2+(b x pi)X+c
(I helped save b3ta! Sir T. Skellington, Wed 9 Nov 2005, 23:22, archived)
# good luck
(GoldenFanjita whistle posse blow! horns crew i can't hear you!, Wed 9 Nov 2005, 23:23, archived)
# ta
but im not going to do it as i cant be arsed typing out the HTML to get sup script
(I helped save b3ta! Sir T. Skellington, Wed 9 Nov 2005, 23:25, archived)
# Trust me, you can't do it that way.
This isn't a polynomial
(Guineapiggy Fuzzeh!, Wed 9 Nov 2005, 23:24, archived)
# that may be true actually
tis just a sign-wave graph

polynomial: -
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(I helped save b3ta! Sir T. Skellington, Wed 9 Nov 2005, 23:28, archived)
# Nicely doodled
Paint?
(Guineapiggy Fuzzeh!, Wed 9 Nov 2005, 23:29, archived)
# yup
let stop this thread...

much to late for maths talk
(I helped save b3ta! Sir T. Skellington, Wed 9 Nov 2005, 23:32, archived)
# err...
cos(x) = 1 - x^2/2! + x^4/4! - ... (a polynomial)

sin(x) = x - x^3/3! + x^5/5! - ... (a polynomial)

aicmfp again!
(I helped save b3ta! grey matter, Wed 9 Nov 2005, 23:39, archived)
# In a polynomial the powers have to be positive integers
Gimmie my five pounds back you fraud!
(Guineapiggy Fuzzeh!, Wed 9 Nov 2005, 23:45, archived)
# i think i should be charging for these lessons...
a) powers don't have to be positive for it to be classed as a polynomial (I think)
b) they aren't even negative in the above.
(I helped save b3ta! grey matter, Wed 9 Nov 2005, 23:51, archived)