Define the set N:
P1: 1 is in N.
P2: If x is in N, then its "successor" x' is in N.
P3: If x isn't 1, then there is a y in N such that y' = x.
Define Addition:
Let a and b be in N.
If b = 1, then define a + b = a' (using P1 and P2).
If b isn't 1, then let c' = b, with c in N (using P3), and define a + b = (a + c)'.
Define 2:
2 = 1'
Proof:
1 is N (by P1)
2 is in N (by P1, P2, and the definition of 2)
Use the first part of the definition of + with a = b = 1.
Then 1 + 1 = 1' = 2
100% Fact
And now... a super-fat penguin:

(Bigness)
N.B. Real, not shopped.
From the 100% Fact challenge. See all 469 entries (closed)
(, Fri 24 Oct 2003, 21:24, archived)
...as two penguins standing back to back.
(, Fri 24 Oct 2003, 21:26, archived)
getting them to stand still while the superglue set
(, Fri 24 Oct 2003, 21:31, archived)
by way of two identical straight lines, you know.
(, Fri 24 Oct 2003, 21:26, archived)
once you have defined everything to do with it, and thats not the commutative law, the commutative law is a * b = b * a, where * is an operation that the field of numbers your using is closed under
(, Fri 24 Oct 2003, 21:49, archived)
if i have two parts of a line, one longer than the other, the short one called a and the long called b, and i put them together in the order a then b, i have the line (a + b). if you put b first then a, you have the line (b + a) and they'd be the same length, so a + b = b + a. 100% of FACT.
(, Fri 24 Oct 2003, 21:53, archived)
while all the other penguins have white only on their fronts?
(, Fri 24 Oct 2003, 21:28, archived)