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[challenge entry] Pac-Floyd

From the Animated Albums challenge. See all 299 entries (closed)

(, Fri 28 May 2010, 12:19, archived)
# That's where I live!
Spot the extra reflection of our bald drummer's head.
(, Fri 28 May 2010, 12:20, archived)
# Which one are you?
(, Fri 28 May 2010, 12:25, archived)
# middle one
(, Fri 28 May 2010, 12:26, archived)
# \o/
(, Fri 28 May 2010, 12:28, archived)
# L-R
Ancient Roman Gardener
Emperor of the Outer Planets
Retired Dragon-Slayer <-- You
Wandering Troubadour / Seasoned Porn Star
Corporate Hit-Man (glasses disguise)
(, Fri 28 May 2010, 12:33, archived)
# spot on except 2
(Hairy Biker)
(, Fri 28 May 2010, 12:36, archived)
# Oh, does he cook?
(, Fri 28 May 2010, 12:38, archived)
# No.
(, Fri 28 May 2010, 12:41, archived)
# :D
(, Fri 28 May 2010, 12:30, archived)
# Oh my. ?
(, Fri 28 May 2010, 12:32, archived)
# PARADOX
(, Fri 28 May 2010, 12:36, archived)
# :)
(, Fri 28 May 2010, 12:40, archived)
# I need a new paradox.
Size 13.
(, Fri 28 May 2010, 12:41, archived)
# The middle member once wee'd on my head and then did a poo in my trouser pocket when I was sleeping
(, Fri 28 May 2010, 12:51, archived)
# Hello mate.
I hope you are coming.
(, Fri 28 May 2010, 13:28, archived)
# haha
super poib
(, Fri 28 May 2010, 12:20, archived)
# what Griffy Said
(, Fri 28 May 2010, 12:22, archived)
# hurrah
we have a new serial killer nutjob
news.bbc.co.uk/1/hi/england/10179073.stm
(, Fri 28 May 2010, 12:24, archived)
# I am the Crossbow Cannibal, destroyer of whores.
(, Fri 28 May 2010, 12:26, archived)
# There was no mention of him eating them. Shit cannibal, really.
(, Fri 28 May 2010, 12:27, archived)
# No mention of him using a crossbow either.
What kind of psychopath are we dealing with here?
(, Fri 28 May 2010, 12:29, archived)
# hmm
on this basis I am the Unicycling Liontamer
(, Fri 28 May 2010, 12:29, archived)
# You must now get famous
As that name needs to be publicly aired.
(, Fri 28 May 2010, 12:34, archived)
# He's a fraud.
He uses a Fiat Panda as he attempts to tame his appetite for big good cake.
(, Fri 28 May 2010, 12:38, archived)
# yes, but my Fiat Panda only has one wheel
(, Fri 28 May 2010, 12:40, archived)
# B&Q shopping list
tarpaulin
gaffer tape
spade
tubular steel chair
champagne
croissant
(, Fri 28 May 2010, 12:39, archived)
# hmm
that random scattering of sites seems desperately random
(, Fri 28 May 2010, 12:30, archived)
# Any three points on a 2d plane make a triangle.
(, Fri 28 May 2010, 12:31, archived)
# what if they're all in a line?
(, Fri 28 May 2010, 12:31, archived)
# Then it's a very pointy triangle.
(, Fri 28 May 2010, 12:33, archived)
# So, any three points on a 1d line make a triangle.
(, Fri 28 May 2010, 12:34, archived)
# I have said something online and am now defending it to the death.
So YES.
(, Fri 28 May 2010, 12:37, archived)
# What? There are four of them, what the hell are you talking about dipshit?
(, Fri 28 May 2010, 12:32, archived)
# ONLY THREE ARE BODY SITES BUMEYES!
(, Fri 28 May 2010, 12:33, archived)
# is it possible to place 3 points on a sphere such that they are all equidistant from each other on the spherical plane?
(, Fri 28 May 2010, 12:42, archived)
# Yes.
(, Fri 28 May 2010, 12:43, archived)
# how?
show me - cos thinking about this give me a brainhurt
(, Fri 28 May 2010, 13:03, archived)
# find a ball and put some dots on it
(, Fri 28 May 2010, 13:08, archived)
# Er, the arc you get from two points on a sphere is the same wherever on the sphere it is, yeah? As long as the points are the same distance apart.
So just take a normal equilateral triangle, bend all the lines into the same arc. The lines are still exactly the same length away from each other on the spherical plane as they were on flat plane.
(, Fri 28 May 2010, 13:11, archived)
# Or find a ball and put some dots on it.
And measure with some thread.
(, Fri 28 May 2010, 13:12, archived)
# That's just my logic, by the way. It may or not apply to reality.
(, Fri 28 May 2010, 13:18, archived)
# my brain hurtses!
(, Fri 28 May 2010, 13:44, archived)
# Imagine an equilateral triangle...
...wedged very tightly inside a globe (so that all the points touch the equator).

Now the distance between all three points around the outside of the globe is equal (it's a third of the equator each).

Is that the sort of thing you meant?
(, Fri 28 May 2010, 14:54, archived)
# Bloody students.
(, Fri 28 May 2010, 12:37, archived)
# Excellent!
(, Fri 28 May 2010, 12:24, archived)
# Yo!

(, Fri 28 May 2010, 12:31, archived)
# Hahahaha!
Grand!


(, Fri 28 May 2010, 12:45, archived)
# Hahaha I like this!
(, Fri 28 May 2010, 12:31, archived)
# oh, lovely work
(, Fri 28 May 2010, 13:28, archived)